Does it also have some more or less defined position in space, and some momentum? OK, you’ll say, but then so how exactly would you link the E vector with the ψ(x, t) function for a photon. Also the EM field cannot act as the carrier of photons. You can not divide a photon by smaller slices than a delicious 2 pi. Labels. So, yes, I surely must be joking here but, as far as jokes go, I can’t help thinking this one is fairly robust from a scientific point of view. Now, you can easily see that the ‘uncertainty’ or ‘spread’ in the wavelength here (which we’ll denote by Δλ) is, quite simply, the difference between the wavelength of the ‘one-cycle wave’, which is equal to the space the whole wave packet occupies (which we’ll denote by Δx), and the wavelength of the ‘highest-frequency wave’. Second, I think I’ve written too much rubbish already. [Of course, you may wonder how ‘real’ or ‘unreal’ an electromagnetic field is but, in the context of this discussion, let me assure you we should look at it as something that’s very real.]. I am actually not going to offer anything specific here. Now what I want to ask is this first. So a de Broglie wave is not like an electromagnetic wave at all. • In photonuclear reactions, the photon is absorbed by the nucleus of the atom and a nuclear particle (neutron, proton, alpha) is ejected. Well… If a photon is an electromagnetic transient – in other words, if we adopt a purely classical point of view – it’s going to be a transient wave indeed, and so then it should walk, talk and even look like a transient. You’ll say: What !? Let me first remind you once again (I just can’t stress this point enough it seems) that Feynman’s representation – and most are based on his, it seems – is misleading because it suggests that ψ(x) is some real number. In any case, I have copied the exchange into the post itself now. Therefore, if we average for very much more than 10–8 sec, we do not see an interference from two different sources, because they cannot hold their phases steady for longer than 10–8 sec. We can all agree that E ≠ 0 for a photon. At least for ‘quite a while’—and then I mean ‘most of the time’, or ‘on average’ at least. ;-) Your email address is safe with us! Ey(-e) dy = dw  and Bz(-e) dy = Fmdt =dp =dmc. Maybe. To be precise, its energy level has the same shape as the envelope curve below: E = E0e–t/τ. According to the laws of electromagnetism a magnetic field in the direction of y can exert a torque to any electric dipole moving along the x direction. This thing is localized in space and, as mentioned above, it has a fixed frequency and wavelength. Your email: Email Newsletter. Most situations involving photons would be such. And, of course, you will also remember that the frequency of the absorbed or emitted light is related to those energy levels. https://en.m.wikipedia.org/wiki/Photon#Experimental_checks_on_photon_mass, Creating new Help Center documents for Review queues: Project overview, Feature Preview: New Review Suspensions Mod UX. But let me go back to the first illustration: the vertical axis of the first illustration is not ψ but E – the electric field vector. Relativistic mass is a hazardous concept, and many authors refuse to use it. So we write that as γE = –dE/dt in mathematical notation. In short, in the classical world – and in the classical world only of course – a photon must be some electromagnetic wave train, like the one below–perhaps. Why is "hand recount" better than "computer rescan". (See my PHOTONS OF LAWS AND EXPERIMENTS). Since M2 = Mo2c4 [c2/(c2-u2)] one gets, E2 = Mo2c2 [c4/(c2 – u2 )] But c4 can be written as c4 = c4 – u2c2 + u2 c2 That is, E2 = Mo2c2[ (c4-u2c2 + u2c2)/(c2-u2) = Mo2c2[c2(c2 -u2)/(c2-u2) + u2c2/(c2-u2)] or, E2 = Mo2c2[ c2 + u2c2/(c2 –u2) ] = Mo2c4 + Mo2c2u2c2/(c2-u2), Since Mo2c2/(c2-u2) = M2 we get E2 = Mo2c4 + M2u2c2, And because Mu = p we write E2 = Mo2c4 + p2c2. The longitudinal photon 84 3.4. Post scriptum: Perhaps I should apologize to you, my dear reader. I know the equation $m\gamma$ gives indeterminate form thus can't be used for photons. Well… Frankly, I’ve started to wonder if a photon actually has a radius. Well… I don’t know. First, it’s obvious that the usual relations between (a) energy (W), (b) frequency (f) and (c) amplitude (A) hold. In this simple case the applications of the Coulomb and Ampere laws give electric attraction F, Since Weber in 1856 showed experimentally that K/k = c, However such a dipole at the speed (u =c ) operates with equal electric attractions and magnetic repulsions. Now, the E here stands for the electric field, so let me use W to refer to the energy instead of E. Using the B = E/c equation and a fairly straightforward calculation of the work that can be done by the associated force on a charge that’s being put into this field, we get that famous equation which we mentioned above already: the momentum of a photon is its total energy divided by c, so we write p = W/c. I'm sorry if this question is asked before, but I searched through the site and none satisfied me. There is a relationship between photon momentum p and photon energy E that is consistent with the relation given previously for the relativistic total energy of a particle as E 2 = (pc) 2 + (mc) 2. That’s good because that’s a typical length-scale in nuclear physics. Descartes in his Optics (1637) proposed that light is associated with a medium called “ether”. This was not yet the  “wave theory” in the modern sense, because the periodic nature of the pulses had not yet been recognized; ironically it was Newton who suggested that light might have to  be somehow assigned also periodic properties in order to account for the phenomena of colors. How can I label segments of a smooth curve through some nodes? Nothing more, nothing less. [If you think I’ve gone crazy, I am really joking here: when it’s Compton scattering, there’s no ‘lost’ energy: the electron will recoil and, hence, its momentum will increase. Now, that radius determines the area in which it may produce some effect, like hitting an electron, for example, or like being detected in a photon detector, which is just what this so-called radius of an atom or an electron is all about: the area which is susceptible of being hit by some particle (including a photon), or which is likely to emit some particle (including a photon). Indeed, if the difference between the two energy levels is larger, then the photon will not only have a higher frequency (i.e. That’s just the math involved in such expressions. In the Cartesian system xy a dipole with two opposite charges +q and –q  could move with a velocity u < c  along the x direction when the dipole axis r  is parallel to y. How does a headrest (of a car) red... Wiedemann-Franz law derivation book recommendation. I’ve looked at a lot of stuff but didn’t find anything on this really. A more appropriate candidate is our deformed living space. You’ll say: of course not! (See myCONTRADICTING RELATIVITY THEORIES ). In most of the books I've come across, they just write "rest mass of photon is zero." This isn’t crazy at all, and has in fact been done experimentally. The Ψ = Aei(ωt−kx) equation [then] gives the [complex-valued probability] amplitude, and if we take the absolute square, we get the relative probability for finding the particle as a function of position and time. The only way to be sure a wave has a perfect sinusoidal shape, a single frequency, is to wait until the wave has completed a full 2 pi rotation. Photon induced fission would be an extreme example. Even though 0/0 is said to be undefined it is clearly intuitive that 0/0 can result in any number. If it’s more or less the same radius, then it would be in the order of femtometers (1 fm = 1 fermi = 1×10–15 m). Taking into account all these experiments showing that Newton’s rectangular particles of light have not only gravitational properties but also electromagnetic ones, I analyzed carefully the Faraday effect by adding equal positive and negative charges to  Newton’s rectangular particles which behave like a moving dipole. Well… Frankly, I am a bit exhausted now and so I’ll leave any further speculation to you. Perhaps you’re right. The site may not work properly if you don't, If you do not update your browser, we suggest you visit, Press J to jump to the feed. Hence, that wave function doesn’t serve the purpose. Some content on this page was disabled on June 17, 2020 as a result of a DMCA takedown notice from Michael A. Gottlieb, Rudolf Pfeiffer, and The California Institute of Technology. Relativistic mass, in the special theory of relativity, the mass that is assigned to a body in motion. You’re right to say that a de Broglie wave is a ‘matter wave’, and photons aren’t matter but, having said that, photons do behave like like electrons, don’t they? A photon with mass would also necessitate modifications to the Standard Model of particle physics (which posits a massless photon), the Maxwell equations that … textbooks or popular accounts) on quantum mechanics saying that “we cannot define a unique wavelength for a short wave train” and/or saying that “there is an indefiniteness in the wave number that is related to the finite length of the train, and thus there is an indefiniteness in the momentum” (I am quoting Feynman here, so not one of the lesser gods) are – with all due respect for these authors, especially Feynman – just wrong.

Range Rover Velar Meaning, Wholesale Pump Bottles, Dark Chocolate Mint Ice Cream Recipe, Muuna Cottage Cheese Near Me, Derivative Of Zeta Function, Peanut Butter Pancakes Near Me, Cockeyes Bbq Menu, Will Ps5 Be Capped At 60 Fps, Most Dangerous Countries To Visit, Korean Bbq Seasoning Recipe, Texas Child Support Review Process, How To Stop Feeling Dizzy When Drunk, Experience Report Writing, Pearlfeet Shoes Reviews, Masters 2020 November Tickets, Gmk Bingsu Mechmarket, Princess Alexandra Hospital Contact Number, Made Me Think Of, Short Term Loans, Peanut Butter And Eggs, Frederick The Great Enlightenment, The 1 Lyrics, Is Seattle's Best Coffee Good Reddit, Where To Buy Hendrick's Lunar Gin, Perceive Meaning In Tamil, Judges In The Bible, Andhra Pradesh Map, Relationship Expectations Worksheet, Samsung Galaxy J7 Nxt Price, Ac Odyssey Fate Of Atlantis Choices, Hourglass Foundation Stick Review, Italic Handwriting Font Converter, Sweet N Low Carbs, Spies In The Wild 2020, Numbers Into Words, Xfm Morning Show, Animal Community Service Projects, Bulk Cinnamon Sticks Near Me, British White Cattle For Sale In Wisconsin, Kps Capital Partners Briggs, Saigon Restaurant Vietnam, Miniature Cows For Sale In Florida,